144=10X^2+4x

Solution for 144=10X^2+4x equation:

144=10X^2+4X

We move all terms to the left:

144-(10X^2+4X)=0

We get rid of parentheses

-10X^2-4X+144=0

a = -10; b = -4; c = +144;
Δ = b2-4ac
Δ = -42-4·(-10)·144
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-76}{2*-10}=\frac{-72}{-20}
=3+3/5
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+76}{2*-10}=\frac{80}{-20}
=-4
$